Given f (z) = (2-3)² +6 for z ≥ 3, find f-¹ (z) and determine the value of f-¹ (42).
O^ f-¹ (2)=√√2-6+3 and f-¹ (42) = -3
O f¹(2)=√√√2-6-3 and f-¹(42) = 3
Ocf-¹ (2)=√√z-6+3 and f-¹ (42) = 9
C
O f¹(2)=√√2-6-3 and f-¹(42) = -9