The general form of the equation of a circle is given by: (x-a)²+(y-b)²=r² where: (a,b) is the center r is the radius Given that the circle with center (-2,6) and cuts point (-2,10), the equation of the circle will be found as follows: the radius of the circle will be: r=√[(x-a)²+(y-b)²] r=√[(-2-(-2))²+(10-6)²] r=√[(-2+2)²+4²] r=√[0+4²] r=4 units hence plugging the values to obtain the equation we get: (x-(-2))²+(y-6)²=4² simplifying we get: (x+2)²+(y-6)²=4²
