jpeters1999
jpeters1999 jpeters1999
  • 23-05-2018
  • Mathematics
contestada

Let E and F be two events that are mutually exclusive and suppose P(E)=.4 and P(F)=.2. Compute P(E intersect F)

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hisroyal1
hisroyal1 hisroyal1
  • 23-05-2018
P (E intersect F) refers to the probability of both events E and F happening at the same time. But since we are told that the events are mutually exclusive, it means that they cannot both occur simultaneously.

Therefore P (E intersect F) = 0
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danielmaduroh
danielmaduroh danielmaduroh
  • 23-05-2018
Given that these two events are mutually exclusive, there's no any relation between them, so:

[tex]P(E\cap F) = P(E)P(F)[/tex]

Then, the probability for this problem is given by:

[tex]P(E\cap F) = (0.4)(0.2)=0.08[/tex]

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