thaliacortes18 thaliacortes18
  • 24-09-2018
  • Mathematics
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How to factor (9x^2-3x-2)(x^2-6)

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gmany
gmany gmany
  • 28-09-2018

[tex](9x^2-3x-2)(x^2-6)=(9x^2-6x+3x-2)(x^2-(\sqrt6)^2)\\\\=[3x(3x-2)+1(3x-2)](x-\sqrt6)(x+\sqrt6)\\\\=(3x-2)(3x+1)(x-\sqrt6)(x+\sqrt6)\\\\Used:\ a^2-b^2=(a-b)(a+b)[/tex]

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