Answer:
[tex]HI=20[/tex]
Step-by-step explanation:
[tex]\widehat{HKL}+\widehat{HKI}=90°, \widehat{HIK}+\widehat{HKI}=90° \\\Rightarrow \bigtriangleup HIK\cong\bigtriangleup HKL\Rightarrow \frac{HI}{HK}=\frac{HK}{HL}\Leftrightarrow HI=\frac{{HK}^{2}}{HL}=\frac{30^{2} }{45} =\frac{900}{45} =20[/tex]
