Victoria183 Victoria183
  • 23-04-2016
  • Mathematics
contestada

compute the value of the discriminant and give the number of real solutions of the quadratic equation. -3x^2+x-1=0

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apologiabiology
apologiabiology apologiabiology
  • 23-04-2016
the discriminant is the bit under the squaer root sign in the quadratic formula

when you have
ax^2+bx+c=0
the discriminant is [tex] b^{2}-4ac [/tex]
if
discriminant>0 then have 2 real solutions/roots
discriminant=0 then have 1 real solution/root
discriminat<0 then have no real roots (2 imaginary roots)


-3x^2+x-1=0
a=-3
b=1
c=-1

[tex] 1^{2}-4(-3)(-1) [/tex]=1-12=-11
-11<0
has zero real solutions

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