meqq33 meqq33
  • 24-04-2019
  • Mathematics
contestada

Write the equation of the circle in general form. Show all of your work.

Write the equation of the circle in general form Show all of your work class=

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PollyP52 PollyP52
  • 23-07-2020

Answer:

x^2 + y^2 + 6x - 8y + 21= 0.

Step-by-step explanation:

The center of this circle is (-3, 4) and the radius id 2.

So in Standard form, the equation is:

(x + 3)^2 + ( y - 4)^2 = 2^2

Converting to General form we have:

x^2 + 6x + 9  + y^2 - 8y + 16 = 4

x^2 + y^2 + 6x - 8y + 9 + 16 - 4 = 0

x^2 + y^2 + 6x - 8y + 21= 0.

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