Answer:
X= 6i
Step-by-step explanation:
We have the following equation:
y^3 - 3y^2 + X - 1 = -i (1),
where X is the missing term.
So, we know that y = 1 + i. Where i = sqrt(-1).
Substituting y = 1 + i in the equation (1):
(1 + i)^3 - 3(1 + i)^2 + X - 1 = -i
(1)^3 + 3(i)(1)^2 + 3(1)(i)^2 + (i)^3 - 3(1 + 2(1)(i) + (i)^2) + X - 1 = -i
Simplifying:
1 + 3i -3i - i - 3(1 + 2i -1) + X - 1 = -i
1 - i -6i + X - 1 = -i
-i - 6i + X = -i
- 6i + X = 0
X= 6i
So the missing term is X= 6i
