bloom25 bloom25
  • 25-05-2019
  • Mathematics
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lily9634
lily9634 lily9634
  • 25-05-2019

Let a,b & c be the number of cookies Adrian, Bobby and Calvin baked respectively.

(a+b+c)/3 =138

(a+b)/2 =136

a+b=272

a=272-b

(b+c)/2 =125

b+c=250

c=250-b

Sub a=272-b and c=250-b into (a+b+c)/3 =138,

(a+b+c)/3 =138

[(272-b)+b+(250-b)]/3 = 138

272-b+b+250-b = 414

-b = -108

b=108

From the above,

a=272-b

=272-108

a=164

c=250-b

=250-108

c=142

∵ a=164

b=108

c=142

∴ Adrian baked 164 cookies.

Bobby baked 108 cookies.

Calvin baked 142 cookies.

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