09ia01
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  • 22-06-2019
  • Mathematics
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konrad509
konrad509 konrad509
  • 22-06-2019

[tex]|\Omega|=8\cdot7=56\\|A|=3\cdot2=6\\\\P(A)=\dfrac{6}{56}=\dfrac{3}{28}\approx10,7\%[/tex]

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