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23-06-2019
Mathematics

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What is the answer to this question

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konrad509 konrad509

23-06-2019

[tex]|\Omega|=9[/tex]

b)

[tex]|A|=2\\\\P(A)=\dfrac{2}{9}\approx22\%[/tex]

c)

[tex]|A|=3\\\\P(A)=\dfrac{3}{9}=\dfrac{1}{3}\approx33\%[/tex]

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