bakilaro102 bakilaro102
  • 25-06-2019
  • Mathematics
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How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1

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LammettHash
LammettHash LammettHash
  • 25-06-2019

There are infinitely many solutions.

Algebraically, we can eliminate [tex]z[/tex] and try to solve for [tex]x,y[/tex]:

[tex]x+y+z=1\implies z=1-x-y[/tex]

Then

[tex]x^2+y^2+(1-x-y)^2=1[/tex]

[tex]\implies x^2+y^2+1-2x+x^2-2y+y^2+2xy=1[/tex]

[tex]\implies x^2-x+y^2-y+xy=0[/tex]

which is the equation of an ellipse.

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