contestada

A person is standing a distance D = 5.8 m in front of a flat, vertical mirror. The distance from the ground to his eyes is H = 1.6 m. An object is placed on the ground a distance d = D/2 = 2.9 m in front of the mirror. At what height h should the bottom of the mirror be so that the person can see the bottom of the object?

Respuesta :

Answer:

it is at height of y = 0.533 m from ground

Explanation:

As per law of reflection we know that angle of incidence = angle of reflection

so here we have

[tex]tan\theta_i = tan\theta_r[/tex]

here we know that

[tex]tan\theta_i = \frac{y}{d}[/tex]

also we have

[tex]tan\theta_r = \frac{H - y}{D}[/tex]

now we have

[tex]\frac{H - y}{D} = \frac{y}{d}[/tex]

here we have

[tex]\frac{1.6 - y}{5.8} = \frac{y}{2.9}[/tex]

[tex]3y = 1.6[/tex]

[tex]y = 0.533 m[/tex]

Ver imagen aristocles

Otras preguntas