Answer:
[tex](x,y,z) = (3, 2-4t, 1+2t)[/tex]
Step-by-step explanation:
Given that a straight line passes through the point P(3,2,1)
Also given that the line is parallel to vector V = (0,-4,2)
This implies that the required line has direction ratios as (0,-4,2)
Hence in cartesian form we can represent the line as
[tex]\frac{x-3}{0} =\frac{y-2}{-4}=\frac{z-1}{2}=t[/tex]
Here t is the parameter
In other words, any point on the line is represented parametrically as
[tex](x,y,z) = (3, 2-4t, 1+2t)[/tex]
