Tehseen
Tehseen Tehseen
  • 24-08-2019
  • Computers and Technology
contestada

A 500 g stone is thrown up
with a velocity of 15ms.
Find its
(i) P.E. at its maximum height
(ii) K.E. when it hits the ground​

Respuesta :

mathmate
mathmate mathmate
  • 25-08-2019

Explanation:

Assuming no loss in energy when going up or down (i.e.neglect air resistance), the energies are the same at the maximum height as well as the ground.

(II) the initial energy is all kinetic (so is the final energy when it hits the ground), so

KE = (mv^2)/2 = 0.5kg * ( (15^2) m^2/s^2 ) /2 = 56.25 J.

(i) PE at top = KE at bottom = 56.25 J.

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