jhapragya22 jhapragya22

21-12-2019
Mathematics

contestada

In ∆ABC, m∠ACB = 90°, m∠A = 40°,
CD (D ∈AB ) is a segment perpendicular to the side AB . Find m∠DBC and m∠BCD.

Respuesta :

MamoonWasim MamoonWasim

21-12-2019

Step-by-step explanation:

u get this diagram^

to find DBC

B+40+90=180

B=50°

to find BCD

CDB is 90° ( since perpendicular to AB)

so taking triangle BCD

90+50+c=180

c=40°

Ver imagen MamoonWasim

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