Dantron3000
Dantron3000 Dantron3000
  • 24-02-2020
  • Mathematics
contestada

I need help on this problem. It is m FEH=126° and m∠EFG=65·

I need help on this problem It is m FEH126 and mEFG65 class=

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MathPhys
MathPhys MathPhys
  • 24-02-2020

Answer:

∠FEH = 117°

∠EHG = 115°

Step-by-step explanation:

Arc angles add up to 360°.

Arc FEH = 126°, so arc FGH = 234°.

Inscribed angles are half the central angle.

Arc FEH = 126°, so ∠FGH = 63°.

Arc FGH = 234°, so ∠FEH = 117°.

Interior angles of a quadrilateral add up to 360°.

So ∠EHG = 360° − 65° − 63° − 117° = 115°.

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