Answer :
By using EDL
a=bq+r
where a is > b
so a =867 and b=255
867=255×3+102
here r≠0 so a=255 and b=102
255=102×2+51
here r≠0 so a=102 and b=51
102=51×2+0
here r=0
so, Hcf of (867,255) is =51
Step-by-step explanation:
Hope it works out!!
Answer:
[tex]51[/tex]
Step-by-step explanation:
[tex]a=bq+r[/tex]
Where [tex]a > b[/tex]
[tex]867=255 \times 3+102[/tex]
[tex]255=102 \times 2+51[/tex]
[tex]102=51 \times 2+0[/tex]
Hcf of 867,255 is 51
