happyhappy4622 happyhappy4622

23-07-2020
Physics

contestada

What is the acceleration of a proton moving with a speed of 9.5 m/s at right angles to a magnetic field of 1.8 T

Respuesta :

nobleswift nobleswift

23-07-2020

Explanation:

F = qvBsin(angle)

F = 1.6 x 10^-19 x 9.5 x 1.8 x Sin (90)

F = 273.6 x 10^-20N

a = F/M

M of a proton = 1.67 x 10^-27kg

a = 273.6 x 10^-20/1.67 x 10^-27

a = 1638323353.29m/s

Answer Link

Otras preguntas

1. Which is NOT a nutrient? Question 1 options: A: protein B: water C: fat D: sugar2.All of the following are reasons why we should eat healthy, EXCEPT:Questio

Why is it important to Grendel that his death be viewed as an accident?

Fill in the missing numbers in these equations (-2)⋅(-4.5)=? (-8.7)⋅(-10)=? (-7)⋅?=14 ?⋅(-10)=90

How many ounces of coffee can be bought for $1.11 if 2 pounds of coffee costs $5.92

at what temperature does water change from a liquid to a gas

which energy source is available in remote areas all around the world? solar wind water biomass or geothermal?

What type of bond is CO2?||

How is velocity affected with rc car pulling wagon

How do I write a polynomial with nine roots? Do I just have to make sure I have x^9 or is that wrong?

An FCC iron-carbon alloy initially containing 0.20 wt% C is carburized at an elevated temperature and in an atmosphere wherein the surface carbon concentration