Answer:
[tex]T_2=35.2\°C[/tex]
Explanation:
Hello,
In this case, since the heat is computed in terms of mass, specific heat and temperature as follows:
[tex]Q=mCp(T_2-T_1)[/tex]
In such a way, for the given heat, we obtain the following temperature:
[tex]T_2=T_1+\frac{Q}{mCp}\\ \\T_2=28.5\°C+\frac{35.9J}{11.7g*0.455\frac{J}{g\°C} }\\ \\T_2=35.2\°C[/tex]
Best regards.
