Respuesta :

Answer:

v = 6.95 m/s

Explanation:

Given that,

A diver is on a board 1.80 m above  the water, s = 1.8 m

The initial speed of the diver, u = 3.62 m/s

Let v is the speed with which she hit the water. It will move under the action of gravity. Using the equation of motion as follows :

[tex]v^2-u^2=2gs\\\\v=\sqrt{u^2+2gs} \\\\v=\sqrt{(3.62)^2+2(9.8)(1.8)} \\\\v=6.95\ m/s[/tex]

So, she will hit the water with a speed of 6.95 m/s.

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