dreamloveandhope26 dreamloveandhope26
  • 23-12-2020
  • Mathematics
contestada

Find < JKL (angle) *
1 point
Given JM = 27, ML = 16, JL = 46, NK = 15, mZKLM = 48°, mZJKM = 78°, and mZMJL = 22°

Respuesta :

mhanifa
mhanifa mhanifa
  • 02-01-2021

Answer:

  • 132°

Step-by-step explanation:

See attached

Given

  • JM = 27, ML = 16, JL = 46, NK = 15, m∠KLM = 48°, m∠JKM = 78°, and m∠MJL = 22°

To find

  • m∠JKL

Solution

JKLM is a parallelogram and therefore has equal opposite angles:

  • ∠JKL = ∠JML and ∠KJM = ∠KLM

Sum of all four is 360°:

  • 2m∠JKL + 2m∠KLM = 360°
  • m∠JKL + m∠KLM = 180°
  • m∠JKL + 48° = 180°
  • m∠JKL = 180° - 48°
  • m ∠JKL = 132°
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