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  • 24-12-2020
  • Mathematics
contestada

Solve algebraically for x:
3600 + 1.02x < 2000 + 1.04x

Respuesta :

838054
838054 838054
  • 24-12-2020

Answer:

Let's solve your inequality step-by-step.

3600+1.02x<2000+1.04x

Step 1: Simplify both sides of the inequality.

1.02x+3600<1.04x+2000

Step 2: Subtract 1.04x from both sides.

1.02x+3600−1.04x<1.04x+2000−1.04x

−0.02x+3600<2000

Step 3: Subtract 3600 from both sides.

−0.02x+3600−3600<2000−3600

−0.02x<−1600

Step 4: Divide both sides by -0.02.

−0.02x

−0.02

<

−1600

−0.02

x>80000

Step-by-step explanation:

Answer Link

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