Answer:
0.0835 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
0.0250 L of 0.105 M HCl react.
0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.
Step 4: Calculate the molarity of NaOH
2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.
M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M
