darcyshay1454 darcyshay1454
  • 22-03-2021
  • Chemistry
contestada

If it takes 38.70 cm^3 of 1.90M NaOH to neutralize 10.30cm^3 of H2SO4 in a battery. What is the concentration of the H2SO4?

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maacastrobr
maacastrobr maacastrobr
  • 23-03-2021

Answer:

3.57 M

Explanation:

The reaction that takes place is:

  • 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we calculate how many NaOH moles reacted, using the given concentration and volume:

  • 38.70 cm³ = 38.70 mL
  • 1.90 M * 38.70 mL = 73.53 mmol NaOH

Then we convert NaOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

  • 73.53 mmol NaOH * [tex]\frac{1mmolH_2SO_4}{2mmolNaOH}[/tex] = 36.765 mmol H₂SO₄

Finally we calculate the concentration of H₂SO₄:

  • 36.765 mmol H₂SO₄ / 10.30 mL = 3.57 M
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