Respuesta :
the answer isÂ
1J, Â 2J, 3J, ...............29D, 30D, 31D = 365 days
2 Â Â 4 Â Â 6 ........................................
 let be S  the value of entire savings
S= Sum 2K= 2Â Sum K Â Â Â = 2Â [365(365+1) / 2],Â
   1<K<365    1<K<365
because  Sum K = n(n+1) /2
        1<K<n
finally S= 133590 pennies
1J, Â 2J, 3J, ...............29D, 30D, 31D = 365 days
2 Â Â 4 Â Â 6 ........................................
 let be S  the value of entire savings
S= Sum 2K= 2Â Sum K Â Â Â = 2Â [365(365+1) / 2],Â
   1<K<365    1<K<365
because  Sum K = n(n+1) /2
        1<K<n
finally S= 133590 pennies