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  • 24-11-2016
  • Mathematics
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derivative of square root of (lnx)

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Edufirst
Edufirst Edufirst
  • 27-11-2016
Use the chain rule

y = √[ln(x)]=> y' = [1/2√(lnx)]*[ln(x)]' = [1/2√(lnx) ] * 1/x = 1 / [2x(√lnx)]
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