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a waitperson pushes the bottom of a glass tumbler full of water across a tabletop at a constant speed. The tumbler and its contents have a mass of 0.70kg, and the coefficient of kinetic friction for the surfaces in contact is 0.41. What force does the waitperson exert on the glass?

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Β Constant speed, therefore net force in the x direction must = 0.Β 

Find normal foce:Β 

Fnet in the y direction is equal to 0.Β 

0 = Fn - FgΒ 
Fn = 0.70 (9.81)Β 
Fn = 6.867 NΒ 

x direction:Β 

Fnet = Fapp - FfΒ 
0 = Fapp - mu(Fn)Β 
Fapp = 0.41(6.867)Β 
Fapp = 2.81547 N

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