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23-10-2021
Mathematics

contestada

HELP PLEASE!!
Write a recursive rule for an=1/3•4^n-1

A.) an=1/3•an-1
B.) an=4•1/3an-1
C.) an=1/3•4an-1
D.) an=4•an-1

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23-10-2021

Answer:

D.) an = 4 * an-1

Step-by-step explanation:

a(n) = (1/3) * 4^(n-1)

a(n-1) = (1/3) * 4^(n-1-1) = (1/3) * 4^(n-2)

Thus,

a(n) = (1/3) * 4 * 4^(n-2) = 4 * [(1/3) * 4^(n-2)] = 4 * a(n-1), so that

a(n) = 4 * a(n-1).

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