By the angle bisector theorem, [tex]\frac{AC}{BC}=\frac{CD}{DB}[/tex]. Plugging in the known side lengths gives [tex]\frac{5.8}{6.2}=\frac{?}{2.7}[/tex]. Solving gives:
[tex]?=(5.8\cdot 2.7)/6.2[/tex]
[tex]\approx 2.5[/tex], rounded to one decimal place.
