thuhlolehlohonolo thuhlolehlohonolo
  • 23-03-2022
  • Mathematics
contestada


In the figure diameter DE is drawn with the midpoint of the circle at C(-3; 2).
EA is a tangent to the circle at E (1,3).

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cks21
cks21 cks21
  • 23-03-2022

Answer:

4

Step-by-step explanation:

[tex]gradient = \frac{y2 - y1}{x2 - x1} [/tex]

[tex]y2 = - 3 \\ y1 = 3 \\ x2 = 2 \\ x1 = 3[/tex]

[tex] \frac{ - 3 - 1}{2 - 3} = \frac{ - 4}{ - 1} = 4[/tex]

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