Answer:
[tex]a_{n}[/tex] = 11 [tex](2)^{n-1}[/tex]
Step-by-step explanation:
the nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
given a₁ = 11 and a₄ = 88 , then
11 r³ = 88 ( divide both sides by 8 )
r³ = 8 ( take cube root of both sides )
r = [tex]\sqrt[3]{8}[/tex] = 2 , then the nth term is
[tex]a_{n}[/tex] = 11 [tex](2)^{n-1}[/tex]
