Answer:
AOD=180°-(32°+90°)=180°-122°=58°(OAD=90°, bcs R (OA) perpendicular on tg (AD)
AC=AOC=AOD=58°
ABC=AC/2=AOC/2=58°/2=29°(the angle inscribed in the circle is half of the arc of the circle under it )
Hope it helps!
