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25-10-2022
Mathematics

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How many solutions will each equation have?x^2+6x+5

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TrejureT728279 TrejureT728279

25-10-2022

To solve the quadratic equation, factor the expression and then clear x from each of the factors obtained.

[tex]\begin{gathered} x^2+6x+5=0 \\ (x+5)(x+1)=0 \\ x+5=0 \\ x=-5 \\ x+1=0 \\ x=-1 \end{gathered}[/tex]

This equation has 2 solutions which are -5 and -1.

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