To answer this question, we can use the two-point form of the line equation:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot(x-x_1)[/tex]Then, we have the points:
(3, 2) --->x1 = 3, y1 = 2
(-2, -18)---> x2 =-2, y2 = -18
Then, we have:
[tex]y-2=\frac{-18-2}{-2-3}\cdot(x-3)\Rightarrow y-2=\frac{-20}{-5}\cdot(x-3)\Rightarrow y-2=4(x-3)[/tex]The question in the slope-intercept form is:
[tex]y=4x-10[/tex]