amberwing17 amberwing17

23-03-2015
Mathematics

contestada

Can some one give me step by step instructions on how to solve this? log(4x+3)=0

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konrad509 konrad509

23-03-2015

[tex]D:4x+3>0\\ D:4x>-3\\ D:x>-\dfrac{3}{4}\\\\ \log(4x+3)=0\\ 10^0=4x+3\\ 1=4x+3\\ 4x=-2\\ x=-\dfrac{2}{4}=-\dfrac{1}{2}[/tex]

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