Respuesta :

   [tex]1√2sinx+1√2cosx=1√2. This can be written as cos(x−π4)=cos(π4) The general solution of this equation ls x−.π4=2nπ±π4,n=0,±1,±2,..., So, x=2nπandx=(4n+1)π2,n=0,±1,±2,±3.... ANSWER: x=2nπandx=(4n+1)π2,n=0,±1,±2,±3....[/tex]