msuniquememphis
msuniquememphis msuniquememphis
  • 22-01-2018
  • Mathematics
contestada

What are the solutions to the equation √x2+2x-10=√x+20

A. x = –6, x = –5
B. x = –6, x = 5
C. x = –5, x = 6
D. x = 5, x = 6

Answer Is B

Respuesta :

carlosego
carlosego carlosego
  • 22-01-2018
√x^2+2x-10=√x+20
 raising both members to the square
 x^2+2x-10=x+20
 rewriting
 x^2+x-30=0
 factoring
 (x+6)(x-5)=0
 therefore the solutions are
 x = –6, x = 5
the answer is 
B. x = –6, x = 5
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