Respuesta :

[tex] \dfrac{-40x^3-12x^2+16x}{-4x} = \dfrac{-4x(10x^2 + 3x - 4)}{-4x} = 10x^2 + 3x - 4[/tex]

Answer: Option A
meowymeowylee
Hi there!

We could solve the equation by dividing each numerator.
We subtract the exponent when we divide x.
ex) 10x³/2x = 5x² because 3-1=2.


Divide -40x³ by -4x first : 10x²
Then divide -12x by -4x : 3x
Lastly divide 16x by -4x : -4

We can add all of them together.

10x² + 3x - 4

So your answer is 1. 10x² + 3x - 4.

Hope this helped :)

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